Edited success rates section

wiki/pages/model.html

@@ -781,12 +781,12 @@
       <p>
         With its current construction, the model implies that the process goes
         to completion; that is, both ligand-dependent and ligand-independent
-        pathways successfully yield a released transcription factor for every
+        pathways successfully yield a released transcription factor for every synNotch
         receptor. The current parameters that represent these processes only
         influence the time-scales on which they occur. However, we know this not
         to be true. There exist experimental data that show a certain proportion
-        of antibody ectodomain expression in the absence of ligand (Roybal et
-        al., 2016; Morsut et al., 2016). Thus, there must be success terms
+        of antibody ectodomain expression in the absence of ligand (Morsut et
+        al., 2016; Roybal et al., 2016). Thus, there must be success terms
         implemented somewhere in this process, since the activation pathways do
         not release all transcription factor. We introduce success rates for
         both ligand-dependent and ligand-independent activation in our model. To
@@ -804,7 +804,7 @@
       <p>We use the following table to outline our procedure:</p>
       <table>
         <tr>
-          <th>"ligand concentration</th>
+          <th>"ligand concentration"</th>
           <th>mCherry response (relative to total)</th>
           <th>Linear relationship between \(\alpha\) and \(\beta\)</th>
           <th>Parameter space of \(\alpha\) and \(\beta\)</th>
@@ -816,14 +816,14 @@
           <td>\[(\alpha, \beta) \in (0.67, 1) \times (0.50, 1)\]</td>
         </tr>
         <tr>
-          <td>\[$10^0 = 1$\]</td>
+          <td>\[10^{0} = 1\]</td>
           <td>50%</td>
           <td>\[\beta = -4.54 \alpha + 2.77\]</td>
           <td>\[(\alpha, \beta) \in (0.39, 0.61) \times (0, 1)\]</td>
         </tr>
         <tr>
           <td>\[10^{0.5} = 3.162\]</td>
-          <td>75&</td>
+          <td>75%</td>
           <td>\[\beta = -14.18 \alpha + 3.79\]</td>
           <td>\[(\alpha, \beta) \in (0.20, 0.27) \times (0, 1)\]</td>
         </tr>